Chapter/Index: Introduction | A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z | Appendix
In crystallographic analysis, a zone axis can be obtained by the cross-product of two vectors (or called faces), e.g. vectors (faces) [hkl] and [pqr] belong to zone [k·r-l·q, l·p-h·r, h·q-k·p]. In this case, the geometry of the zone axis [u v w] and the planes (h k l) and (p q r), which belong to the zone, is shown in Figure 2967. The line (their zone axis) of the intersection of the two planes is given by the cross product of their normals (reciprocal lattice vectors): Here, the "x" in Equation 2967a denotes a cross product. Figure 2967. Zone axis [u v w] of the planes with indices (h k l) and (p q r).
Any other vector (face) [efg] belongs to the same zone if it is some linear combination of [hkl] and [pqr], for instance, e = 2h-3p, f = 2k-3q, etc. For instance, vectors [110] and [010] belong to [1·0-0·1, 0·0-1·0, 1·1-1·0], or [001] (e.g. BCC). The zone axis of vectors [211] and [124] is [1·4-1·2, 1·1-2·4, 2·2-1·1] or [2,-7,1]. And, the vectors (faces) [335], [546], [1,-1,-3], etc. also belong to this zone. A common cross-product formula to find a zone axis is given by: For any plane (hkl) that belongs to the zone axis [u v w], the following relationship is satisfied: hu + kv + lw = 0 --------------------- [2967f]
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